SOLUTION: Find the area of the rectangle or square. This shape is a square The right side is = 1 1/3 yd The bottom side is = 1 1/3 yd Any help wtih this equation would be <b>Grea

Algebra ->  Equations -> SOLUTION: Find the area of the rectangle or square. This shape is a square The right side is = 1 1/3 yd The bottom side is = 1 1/3 yd Any help wtih this equation would be <b>Grea      Log On


   

Question 111832: Find the area of the rectangle or square.
This shape is a square
The right side is = 1 1/3 yd
The bottom side is = 1 1/3 yd
Any help wtih this equation would be Greatly appreciated.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
1%261%2F3 Start with the given mixed number

3%2A1=3 Multiply the denominator 3 by the whole number 1 to get 3

3%2B1=4. Add 3 to the numerator 1 to get 4. This final result is the new numerator

4%2F3 Place the new numerator over the same denominator

So the mixed number 1%261%2F3 is equivalent to the improper fraction 4%2F3




Now multiply the base of 4%2F3 by the height of 4%2F3 (remember these are both equivalent to 1%261%2F3) to get

%284%2F3%29%284%2F3%29=%284%2A4%29%2F%283%2A3%29=16%2F9


So the area of the square is 16%2F9