SOLUTION: Find the value of A and B if sqrtA * sqrtB = 4 sqrtA - sqrtB = sqrt8

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Question 1118066: Find the value of A and B if
sqrtA * sqrtB = 4
sqrtA - sqrtB = sqrt8

Found 2 solutions by math_helper, ikleyn:
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
I think someone solved this one but may have left some work for you the student. I will do all the steps but you should try to understand them if you expect to learn this.
(1) +sqrt%28A%29%2Asqrt%28B%29+=+4+
(2) +sqrt%28A%29-sqrt%28B%29+=+sqrt%288%29+
(1) —> +sqrt%28A%29+=+4%2Fsqrt%28B%29+
Substitute RHS of this for +sqrt%28A%29+ in (2):
+4%2Fsqrt%28B%29+-+sqrt%28B%29+=+sqrt%288%29+
Here I let +u+=+sqrt%28B%29+
+4%2Fu++-+u+=+sqrt%288%29+
++u%5E2+%2B+%28sqrt%288%29%29u+-+4+=+0+
Complete the square: add %28sqrt%288%29%2F2%29%5E2 to both sides. Note that sqrt%288%29+=+sqrt%284%2A2%29+=+2sqrt%282%29+ so we are simply adding 2 to both sides:
++u%5E2+%2B+%28sqrt%288%29%29u+%2B2+-+4+=+2+
Re-write, and move the 4 to the RHS:
++%28u+%2B+sqrt%282%29%29%5E2+=+6+
Take square root of both sides:
+++u+%2B+sqrt%282%29+=+sqrt%286%29+
+sqrt%28B%29+=+u+=+sqrt%286%29+-+sqrt%282%29+ (*)


Squaring this gives B:
++highlight%28+B+=+8-4%2Asqrt%283%29+%29+

Using (*) and (2): +sqrt%28A%29+-+sqrt%286%29+%2B+sqrt%282%29+=+sqrt%288%29+ —> +sqrt%28A%29+=+sqrt%286%29%2Bsqrt%282%29+

Squaring this gives A:
+highlight%28+A+=+8%2B4%2Asqrt%283%29+%29+


Check:
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Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
This problem can be solved in more simple way.

Let x be the value (now unknown) exactly half-way between  sqrt%28A%29  and  sqrt%28B%29,  i.e.  x = %28sqrt%28A%29+%2B+sqrt%28B%29%29%2F2.


So then  sqrt%28A%29 = x + sqrt%288%29%2F2 = x + sqrt%282%29,  sqrt%28B%29 = x - sqrt%288%29%2F2 = x+-+sqrt%282%29.


Then from  sqrt%28A%29%2Asqrt%28B%29 = 4  you get


%28x%2Bsqrt%282%29%29%2A%28x-sqrt%282%29%29 = 4,   or


x%5E2+-+%28sqrt%282%29%29%5E2 = 4,   which is the same as


x%5E2+-+2 = 4,   which implies  x%5E2 = 4 + 2 = 6;  hence,  x = sqrt%286%29.


Then  sqrt%28A%29 = sqrt%286%29+%2B+sqrt%282%29  ====>  square both sides  ====>  A = 8+%2B+2%2Asqrt%2812%29 = 8+%2B+4%2Asqrt%283%29.

      sqrt%28B%29 = sqrt%286%29+-+sqrt%282%29  ====>  square both sides  ====>  B =  8+-+2%2Asqrt%2812%29 = 8-4%2Asqrt%283%29.