SOLUTION: I'm trying to brush up on my math skills 45 years after high school. Most of it is pretty basic but this one has me stumped.
( b + a ) / ab = 1 / f
solve for b
I've mashed
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-> SOLUTION: I'm trying to brush up on my math skills 45 years after high school. Most of it is pretty basic but this one has me stumped.
( b + a ) / ab = 1 / f
solve for b
I've mashed
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Question 1116106: I'm trying to brush up on my math skills 45 years after high school. Most of it is pretty basic but this one has me stumped.
( b + a ) / ab = 1 / f
solve for b
I've mashed it all around but I just can't tease out the b. I even tried working backward from the answer. How is this done? The answer in the back of the book is:
b = fa / ( a - f ) or b = -fa / ( f - a )
if you're interested.
Thank you,
Jim Found 2 solutions by ankor@dixie-net.com, MathTherapy:Answer by ankor@dixie-net.com(22740) (Show Source):
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I'm trying to brush up on my math skills 45 years after high school. Most of it is pretty basic but this one has me stumped.
( b + a ) / ab = 1 / f
solve for b
I've mashed it all around but I just can't tease out the b. I even tried working backward from the answer. How is this done? The answer in the back of the book is:
b = fa / ( a - f ) or b = -fa / ( f - a )
if you're interested.
Thank you,
Jim
ab = f(b + a) ------ Cross-multiplying
ab = bf + af
ab - bf = af
b(a - f) = af