SOLUTION: [1/(a-b) - 1/(a+b)] / [1/(a+b) + 1/(a+b)]

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Question 1115756: [1/(a-b) - 1/(a+b)] / [1/(a+b) + 1/(a+b)]
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
%281%2F%28a-b%29-1%2F%28a%2Bb%29%29%2F%281%2F%28a%2Bb%29%2B1%2F%28a%2Bb%29%29

%281%2F%28a-b%29-1%2F%28a%2Bb%29%29%2F%282%2F%28a%2Bb%29%29

Multiply entire expression by %28%28a-b%29%28a%2Bb%29%29%2F%28%28a-b%29%28a%2Bb%29%29.

%28%28a%2Bb%29-%28a-b%29%29%2F%282%28a-b%29%29

%282b%29%2F%282%28a-b%29%29

highlight_green%28b%2F%28a-b%29%29


Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
The numerator = 1%2F%28a-b%29+-+1%2F%28a%2Bb%29 = %28a%2Bb%29%2F%28%28a-b%29%2A%28a%2Bb%29%29+-+%28a-b%29%2F%28%28a-b%29%2A%28a%2Bb%29%29 = %28a%2Bb-a%2Bb%29%2F%28%28a-b%29%2A%28a%2Bb%29%29 = %282b%29%2F%28%28a-b%29%2A%28a%2Bb%29%29.


The denominator = 1%2F%28a%2Bb%29+%2B+1%2F%28a%2Bb%29 = 2%2F%28a%2Bb%29.


The fraction = numerator%2Fdenominator = %28%282b%29%2F%28%28a-b%29%2A%28a%2Bb%29%29%29%2F%282%2F%28a%2Bb%29%29 = b%2F%28a-b%29.

Solved.

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Ignore writing by  @josgarithmetic,  because it is the way to  NOWHERE.