SOLUTION: Find an interval over which the function f(x)=(x+5)^3(x-4)^2 is decreasing.

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Question 1110853: Find an interval over which the function f(x)=(x+5)^3(x-4)^2 is decreasing.


Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The interval over which the function f%28x%29 is decreasing
is the interval where its derivative is negative.

f%28x%29=%28x%2B5%29%5E3%28x-4%29%5E2 can be considered to be the product of the functions
u%28x%29=%28x%2B5%29%5E3 and v%28x%29=%28x-4%29%5E2

You must have learned that for a product function f=u%2Av ,
the derivative %22f+%27+%22 can be calculated
from the factor functions, u and v ,
and their derivatives, %22u+%27+%22 and %22v+%27+%22 , as
%22f+%27%22+=%22u+%27+%22%2Av%2B%22v+%27%22%2Au .
In this case, %22u+%27%22=3%28x%2B5%29%5E2 and %22v+%27%22=2%28x-4%29 , so

The zeros of that derivative are x=-5 , x=4 and x=2%2F5 .
Because x=-5 has even multiplicity
(multiplicity is 2 because (%28x-5%29 is squared).
%22f+%27%22 does not change sign at x=5 .
the derivative changes sign at the other two roots,
and it is obviously positive for x%3E4 ,
so it is negative only in the interval %22%28+2+%2F+5+%2C+4+%29%22 .