Question 111048: Steve hit four more home runs than twice the number of home runs Larry hit. Together they hit 10 home runs. How many home runs did Steve hit?
Found 2 solutions by stanbon, oberobic:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Steve hit four more home runs than twice the number of home runs Larry hit. Together they hit 10 home runs. How many home runs did Steve hit?
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Always let the smaller quantity be "x"; that way you avoid fractions.
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Let # of Larry home runs be "x".
Then Steve his 2x+4 home runs.
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EQUATION:
x + 2x+4 = 10
3x = 6
x = 2 (Larry hit two home runs)
2x+4 = 8 (Steve hit eight home runs)
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Cheers,
Stan H.
Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! As a general rule, always set the smallest quantity or amount to x.
In this case, we are told Steve hit more than Larry, so let x = number of home runs by Larry.
Since there were 10 home runs in total, then Steve hit 10-x.
This is another general principle for solving word problems: When you know the total, use it to define one of the unknowns.
The other thing we are told is that Steve hit 4 more (that means to add 4) to twice the number of homes hit by Larry (that means 2x).
So Steve hit 2x+4, and Larry hit x.
We know the total is 10, so we now have all the pieces for an equation:
Combining the x terms, we have
Now we subtract 4 from both sides
Dividing through by 3 to remove the coefficient on x
 , which we defined as the number hit by Larry.
 , which we defined as the number hit by Steve.
Checking,  .
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