Question 1107039: Solve for x. x!=1 (two answers are required)
According to math_tutor (887), we can solve equations with factorials with the below method:
"There is no easy inverse function for the factorial (gamma function).
However, given x! = (a value) you can start by dividing by 2, then 3, then 4, etc. When your division produces a value of 1 then that last division is the value of x."
Using this method, I can solve the equation (but just one value):
x!=1
x!/1=1/1
1=1
Therefore, x=1
BUT is there any way (a process) that can solve x=0?
Answer by Edwin McCravy(20055)   (Show Source):
You can put this solution on YOUR website!
0! = 1! = 1
The idea of the factorial (in simple terms) is used to
compute the number of permutations of arranging a set
of n numbers. It can be said that an empty set can only
be ordered one way, so 0! = 1
That's informal. Moe formally, we can do this:
By definition of factorial,
n! = n•(n-1)! where n > 0
1! = 1•(1-1)!
1 = 1•0!
1 = 0!
Edwin
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