SOLUTION: Solve for x.
x^x=1 (Two answers are required)
According to math_helper (887), he/she said the following:
x^x=1
xXIn(x)=In(1)
xXIn(x)=0
Now, here comes the trouble, BUT if I p
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-> SOLUTION: Solve for x.
x^x=1 (Two answers are required)
According to math_helper (887), he/she said the following:
x^x=1
xXIn(x)=In(1)
xXIn(x)=0
Now, here comes the trouble, BUT if I p
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Question 1107037: Solve for x.
x^x=1 (Two answers are required)
According to math_helper (887), he/she said the following:
x^x=1
xXIn(x)=In(1)
xXIn(x)=0
Now, here comes the trouble, BUT if I plug in, 0 and 1 are valid,
as 0^0=1, 1^1=1.
But, if I use his/her way:
Predict x=0
0XIn(0)=0
Error=0
???Not valid?
Predict x=1
1XIn(1)=0
0=0
Valid.
So 0 is not valid for x? If not, what's the process to find/prove out x=0? Found 2 solutions by ikleyn, Alan3354:Answer by ikleyn(52781) (Show Source):
