SOLUTION: The total energy in megawatt-hour used by a town is given by
E(t)=400t+(2400/π)sin(πt/12)
where t>=0 is measured in hours,with t=0 corresponding to noon.At what tim
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-> SOLUTION: The total energy in megawatt-hour used by a town is given by
E(t)=400t+(2400/π)sin(πt/12)
where t>=0 is measured in hours,with t=0 corresponding to noon.At what tim
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Question 1105000: The total energy in megawatt-hour used by a town is given by
E(t)=400t+(2400/π)sin(πt/12)
where t>=0 is measured in hours,with t=0 corresponding to noon.At what time of the day is the rate of energy consumption is minimum?
You can put this solution on YOUR website! The total energy in megawatt-hour used by a town is given by
E(t)=400t+(2400/π)sin(πt/12)
where t>=0 is measured in hours,with t=0 corresponding to noon.At what time of the day is the rate of energy consumption is minimum?
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E'(t) = = 0
Solve for t.
