SOLUTION: It takes Tom twice as long as Sam to drive from A to B. Sam is at A and Tom is at B. If they start driving towards each other at the same time, they will meet one hour later. If in

Algebra ->  Equations -> SOLUTION: It takes Tom twice as long as Sam to drive from A to B. Sam is at A and Tom is at B. If they start driving towards each other at the same time, they will meet one hour later. If in      Log On


   



Question 1104182: It takes Tom twice as long as Sam to drive from A to B. Sam is at A and Tom is at B. If they start driving towards each other at the same time, they will meet one hour later. If instead they started driving in the same direction ( with Sam driving towards B), how long before they meet?
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let T be the Tom' speed and S be the Sam' speed.

    (the same consistent units of speed are used).


Then from he condition,  

S = 2T         (1)   ("It takes Tom twice as long as Sam to drive from A to B.")
S + 2T = D     (2)    ("If they start driving towards each other at the same time, they will meet one hour later.")

where D is the distance between A and B.


If instead they started driving in the same direction (with Sam driving towards B), 

then T has head start D, the relative speed is S-T  and the time before Sam will catch up Tom is


time = D%2F%28S-T%29 =          (replace D with S + 2T, according to (2) )

     = %28S+%2B+2T%29%2F%28S-T%29 =          (replace S with 2T, according to (1) )

     = %282T+%2B+2T%29%2F%282T-T%29 = %284T%29%2FT = 4 hours.


Answer.  It will take 4 hours before Sam will catch up Tom.

Solved.

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See these relevant lessons on Travel and Distance
    - Travel and Distance problems
    - Travel and Distance problems for two bodies moving in opposite directions
    - Travel and Distance problems for two bodies moving in the same direction (catching up)
in this site.