SOLUTION: make x the subject y^2=(8x+2)^2/(4x+2)

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Question 110329: make x the subject y^2=(8x+2)^2/(4x+2)
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
make x the subject y%5E2=%288x%2B2%29%5E2%2F%284x%2B2%29
y%5E2=%288x%2B2%29%288x%2B2%29%2F%284x%2B2%29
y%5E2=2%284x%2B1%29%288x%2B2%29%2F2%282x%2B1%29....cancel 2 in both nominator and denominator

y%5E2=%284x%2B1%29%288x%2B2%29%2F%282x%2B1%29......multiply terms in nominator

y%5E2=%2832x%5E2+%2B+8x+%2B+8x+%2B+2%29%2F%282x%2B1%29......

y%5E2=%2832x%5E2+%2B+16x+%2B+2%29%2F%282x%2B1%29......divide each term in nominator by 2

y%5E2=%2816x%5E2+%2B+8x+%2B+1%29%2F%282x%2B1%29......replace 8x with 4x+%2B+4x

y%5E2=%2816x%5E2+%2B+4x%2B+4x+%2B+1%29%2F%282x%2B1%29......group the first two terms together and the last two terms together

y%5E2=%28%2816x%5E2+%2B+4x%29%2B+%284x+%2B+1%29%29%2F%282x%2B1%29......factor a 4x out of the first group and 1 out of the second group
y%5E2=%284x%284x+%2B+1%29%2B+1%284x+%2B+1%29%29%2F%282x%2B1%29......we have a common term %284x+%2B+1%29
y%5E2=%284x+%2B+1%29%284x+%2B+1%29%2F%282x%2B1%29......