SOLUTION: A pilot flew his​ single-engine airplane 90 miles with the wind from City A to above City B. He then turned around and flew back to City A against the wind. If the wind was a
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Question 1102559: A pilot flew his single-engine airplane 90 miles with the wind from City A to above City B. He then turned around and flew back to City A against the wind. If the wind was a constant 20 miles per hour, and the total time going and returning was 1.3 hours, find the speed of the plane in still air. Found 2 solutions by ikleyn, josgarithmetic:Answer by ikleyn(52777) (Show Source):
You can put this solution on YOUR website! .
A pilot flew his single-engine airplane 90 miles with the wind from City A to above City B. He then turned around
and flew back to City A against the wind. If the wind was a constant 20 miles per hour, and the total time
going and returning was 1.3 hours, find the speed of the plane in still air.
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Let x be the speed of plane "at no wind", in miles per hour (mph).
Then the speed with the wind is (x+30) mph,
the speed against the wind is (x-30) mph.
Then the "time equation" is
+ = 1.3 hours.
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90*(x+20) + 90*(x-20) = 1.3*(x^2-400) ====>
180x = 1.3x^2 - 1.3*400 ====> 1.3x^2 - 180x - 1.3*400 = 0 ====>
= = .
Only positive root makes sense x = = 141.29.
Answer. The speed of the plane "at no wind" is 141.29 miles per hour.