SOLUTION: Find two consecutive integers such that three times the second integer is fourteen less than five times the first integer. Find the integers
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Question 1096292: Find two consecutive integers such that three times the second integer is fourteen less than five times the first integer. Find the integers
You can put this solution on YOUR website! Find two consecutive integers
n, (n+1)
such that three times the second integer is fourteen less than five times the first integer.
3(n+1) = 5n - 14
3n + 3 = 5n - 14
3 + 14 = 5n - 3n
17 = 2n
n = 17/2
n = 8.5; obviously something wrong here.
:
They do satisfy the equation but are not integers. A bad problem
