SOLUTION: A population of bacteria has 1175 bacteria in its starting population. The half-life of this particular type of bacteria is 11 days. (This means that every 11 days the population d

Algebra ->  Equations -> SOLUTION: A population of bacteria has 1175 bacteria in its starting population. The half-life of this particular type of bacteria is 11 days. (This means that every 11 days the population d      Log On


   



Question 1096197: A population of bacteria has 1175 bacteria in its starting population. The half-life of this particular type of bacteria is 11 days. (This means that every 11 days the population decreases by half.) Write a function B(d) that represents the amount of bacteria B in the population after d days.
B(d)=

In this and every exponential problem, if you want to use decimals use 7 or 8 decimal places. If that doesn't work you will have to use fractions.

Answer by greenestamps(13198) About Me  (Show Source):
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With a half life of 11 days, the number of half lives in d days is d/11.
Since the original number of bacteria (1175) is getting multiplied by 1/2 every d/11 days, the exponential function is

B%28d%29+=+1175%2A%281%2F2%29%5E%28d%2F11%29