SOLUTION: 7x – 2(x + 5) = 1 – 2(4 – 3x) is x = -3. Using LS = RS and substitution, verify that this answer is correct. I don't know how to use LS = RS so I need help with that.

Algebra ->  Equations -> SOLUTION: 7x – 2(x + 5) = 1 – 2(4 – 3x) is x = -3. Using LS = RS and substitution, verify that this answer is correct. I don't know how to use LS = RS so I need help with that.      Log On


   



Question 1090080: 7x – 2(x + 5) = 1 – 2(4 – 3x) is x = -3.
Using LS = RS and substitution, verify that this answer is correct.
I don't know how to use LS = RS so I need help with that.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Left side = Right side
When there is an " = " sign, you are saying
that this must be true.
You just can't say something that is obviously
wrong, like +4+=+7+
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The rule that must be followed is:
Whatever you do to the left side, you MUST
also do to the right side also
-----------------------------
+7x+-+2%2A%28+x+%2B+5+%29+=+1+-+2%2A%28+4+-+3x+%29+
I want to get all the terms with +x+ in them
on one side. First I'll get rid of the parenthses
+7x+-+2x+-+10+=+1+-+8+%2B+6x+
Subtract +6x+ from both sides
+7x+-+2x+-+6x+-+10+=+1+-+8+
Combine terms on both sides
+7x+-+8x+-+10+=+-7+
Do the subtraction of +x+ terms on the left side
+-x+-+10+=+-7+
Add +10+ to both sides
+-x+=+3+
Now multiply both sides by +-1+
+x+=+-3+
Hope this helps