SOLUTION: Find the equation of a circle with center (2,1) and passing through the point (4,3).

Algebra ->  Equations -> SOLUTION: Find the equation of a circle with center (2,1) and passing through the point (4,3).      Log On


   

Question 1089829: Find the equation of a circle with center (2,1) and passing through the point (4,3).
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

the equation of a circle:
%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2 where h and k are x and y coordinates o the center
if a circle have center at (2,1), than h=2 and k=1; so, we have
%28x-2%29%5E2%2B%28y-1%29%5E2=r%5E2
and if passing through the point (4,3), we will use it to find radius r%5E2

%284-2%29%5E2%2B%283-1%29%5E2=r%5E2
2%5E2%2B2%5E2=r%5E2
r%5E2=8
and your circle is: %28x-2%29%5E2%2B%28y-1%29%5E2=8