SOLUTION: what are x and y in the following two peoblems? 6xt40y=554 and 8x+20y=472
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Question 1089224
:
what are x and y in the following two peoblems?
6xt40y=554 and 8x+20y=472
Answer by
rothauserc(4718)
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1) 6x +40y = 554
:
2) 8x+ 20y = 472
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multiply equation 2 by 2
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3) 16x +40y = 944
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subtract equation 1) from equation 3)
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4) 10x = 390
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x = 39
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substitute for x in equation 1)
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6(39) +40y = 554
:
234 +40y = 554
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40y = 320
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y = 8
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x = 39 and y = 8
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check the solution by substituting in equation 2 for x and y
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8(39) + 20(8) = 472
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312 + 160 = 472
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472 = 472
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our answer checks
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