SOLUTION: Dominique flew her light plane from Buffalo to Cleveland at an land one half the Dominique average speed of 150 km/h. She waited at Cleveland one half the time that she had been in

Algebra ->  Equations -> SOLUTION: Dominique flew her light plane from Buffalo to Cleveland at an land one half the Dominique average speed of 150 km/h. She waited at Cleveland one half the time that she had been in      Log On


   

Question 1088222: Dominique flew her light plane from Buffalo to Cleveland at an land one half the Dominique average speed of 150 km/h. She waited at Cleveland one half the time that she had been in the air on her trip to Cleveland. Returning home, she took a route that was 60 km longer and flew at an average speed of 180 km/h. If the total trip took five hours, how long did she stay in Cleveland?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
t= time Dominique waited at Cleveland (in hours)
2t= time in the air on her trip to Cleveland (in hours)
150%2A%282t%29=300t= distance flown on her trip to Cleveland (in km)
300t%2B60= distance flown on the return trip (in km)
%28300t%2B60%29%2F180=%285%2F3%29t%2B1%2F3= time in the air on the return trip (in hours)
Adding times,
2t%2Bt%2B%285%2F3%29t%2B1%2F3=5
Multiplying both sides of the equation times 3 to eliminate denominators,
6t%2B3t%2B5t%2B1=15
14t%2B1=15
14t=15-1
14t=14
t=1
Dominique waited at Cleveland for highlight%281+hour%29 .