SOLUTION: if a^2 + 1 = a find the value of a^3.

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Question 1087364: if a^2 + 1 = a find the value of a^3.

Found 4 solutions by jim_thompson5910, Edwin McCravy, MathTherapy, ikleyn:
Answer by jim_thompson5910(35256) About Me  (Show Source):
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a%5E2+%2B+1+=+a Start with the given equation

a%5E2+%2B+1-1+=+a-1 Subtract 1 from both sides

a%5E2+=+a-1 Simplify. Call this equation (1)

a%5E2+%2B+1+=+a Go back to the original equation

a%2A%28a%5E2+%2B+1%29+=+a%2Aa Multiply both sides by 'a'

a%5E3+%2B+a+=+a%5E2 Distribute

a%5E3+%2B+a-a+=+a%5E2-a Subtract 'a' from both sides to isolate the a^3 term

a%5E3+=+a%5E2+-+a Simplfy

a%5E3+=+a-1+-+a Replace the a%5E2 with a-1. See equation (1) above.

a%5E3+=+-1 Simplify. Note how the 'a' terms on the right side cancel out

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An alternative is to solve for 'a' using the quadratic formula (after you get everything to one side and have a%5E2-a%2B1+=+0). That leads to two complex solutions in the form a%2Bbi. After cubing both sides of the two equations you'll lead to a%5E3+=+-1. This method is a lot longer than the first method so I find it ideal to follow the first method.

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No matter which method you follow, the final answer is -1

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
 

if a^2 + 1 = a find the value of a^3.

    a² + 1 = a

a² - a + 1 = 0

We recognize the left side as one of the factors in
the factorization of the sum of two cubes 

a³ + 1 = (a + 1)(a² - a + 1) 

So we multiply both sides by (a + 1)

(a + 1)(a² - a + 1) = 0(a + 1)

             a³ + 1 = 0
                 
                 a³ = -1

                

Edwin

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

if a^2 + 1 = a find the value of a^3.
matrix%281%2C3%2C+a%5E2+%2B+1+=+a%2C+%22======%3E%22%2C+a%5E2+-+a+=+-+1%29
a%5E2+=+a+-+1
a%28a%5E2%29+=+a%28a+-+1%29 ------- Multiplying each side by a
a%5E3+=+a%5E2+-+a
highlight_green%28matrix%281%2C5%2C+a%5E3%2C+%22=%22%2C+a%5E2+-+a%2C+%22=%22%2C+-+1%29%29

Answer by ikleyn(52780) About Me  (Show Source):
You can put this solution on YOUR website!
.
What is interesting in this problem (and why I am writing these lines) 

is that a%5E3 = -1 ,  BUT  a =/= -1  (!!).



The value of  "a"  in this problem is one of the two complex cubic roots of -1.