SOLUTION: <pre> How for can a car run for (7x-2y)hours at (49x<sup>2</sup>+14xy+4y<sup>2</sup>)kilometers per hour?</pre>

Algebra ->  Equations -> SOLUTION: <pre> How for can a car run for (7x-2y)hours at (49x<sup>2</sup>+14xy+4y<sup>2</sup>)kilometers per hour?</pre>       Log On


   



Question 1085460:
How for can a car run for (7x-2y)hours at
(49x2+14xy+4y2)kilometers per hour?


Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
Time = (7x-2y) hours
Rate = (49x2+14xy+4y2) kilometers per hour

The formula is

Distance = Rate × Time

Distance = (49x2+14xy+4y2)(7x-2y)

Now simplify this:

If you switch the factors (7x-2y)(49x2+14xy+4y2) 
and recognize this as the factorization of (7x)3-(2y)3,
then you'll know this is the answer. Otherwise, multiply it
all the way out and everything will cancel except 343x3-8y3, 
which = (7x)3-(2y)3.

Edwin