SOLUTION: X^2 + x + 1 = 0. 5x^2 - 5x - 6 = 0. 9x^2 - 6x + 1 = 0

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Question 1083581: X^2 + x + 1 = 0. 5x^2 - 5x - 6 = 0. 9x^2 - 6x + 1 = 0
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
X^2 + x + 1 = 0. 5x^2 - 5x - 6 = 0. 9x^2 - 6x + 1 = 0
x=(1/2)(-1+/-sqrt (1-4))=(1/2)+/- i * sqrt (3)
5x^2-5x-6=0
x=(1/10)(5+/-sqrt(25+120))=(1/10)(5+/-sqrt(145))
9x^2-6x+1=0
this factors into a perfect square (3x-1)^2=0, so x=(1/3)
1-2+1=0 checks.
One graph (the first problem) has no x-intercept, and the other has numerical roots of about 1.7 and -0.7.
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E2%2Bx%2B1%2C5x%5E2-5x-6%29