SOLUTION: If (a_1,a_2,..a_17) satisfy a_1 + a_2 + a_3 = 1, a_2 + a_3 + a_4 = 2, a_3 + a_4 + a_5 = 3, a_{15} + a_{16} + a_{17} = 15, a_{16} + a_{17} + a_{1} = 16, a_{17} + a_{1}

Algebra ->  Equations -> SOLUTION: If (a_1,a_2,..a_17) satisfy a_1 + a_2 + a_3 = 1, a_2 + a_3 + a_4 = 2, a_3 + a_4 + a_5 = 3, a_{15} + a_{16} + a_{17} = 15, a_{16} + a_{17} + a_{1} = 16, a_{17} + a_{1}      Log On


   



Question 1078619: If (a_1,a_2,..a_17) satisfy
a_1 + a_2 + a_3 = 1,
a_2 + a_3 + a_4 = 2,
a_3 + a_4 + a_5 = 3,
a_{15} + a_{16} + a_{17} = 15,
a_{16} + a_{17} + a_{1} = 16,
a_{17} + a_{1} + a_{2} = 17,

what is the value of a_{17}?
what is the value of $a_{17}$?

Answer by ikleyn(52875) About Me  (Show Source):
You can put this solution on YOUR website!
.
I read your problem in THIS way:
If (a%5B1%5D,a%5B2%5D, . . . a%5B17%5D) satisfy

a%5B1%5D+%2B+a%5B2%5D+%2B+a%5B3%5D = 1, 
a%5B2%5D+%2B+a%5B3%5D+%2B+a%5B4%5D = 2,
a%5B3%5D+%2B+a%5B4%5D+%2B+a%5B5%5D = 3, 
. . . . . . . . .        <<<---=== I added THIS which means that there are similar equations for all intermediate indexes
a%5B15%5D+%2B+a%5B16%5D+%2B+a%5B17%5D = 15, 
a%5B16%5D+%2B+a%5B17%5D+%2B+a%5B1%5D = 16, 
a%5B17%5D+%2B+a%5B1%5D+%2B+a%5B2%5D = 17
 
what is the value of a%5B17%5D ?
~~~~~~~~~~~~~
Below is the system of equations written in full

a%5B1%5D+%2B+a%5B2%5D+%2B+a%5B3%5D = 1,        (1)
a%5B2%5D+%2B+a%5B3%5D+%2B+a%5B4%5D = 2,        (2)
a%5B3%5D+%2B+a%5B4%5D+%2B+a%5B5%5D = 3,        (3) 
a%5B4%5D+%2B+a%5B5%5D+%2B+a%5B6%5D = 4,        (4) 
a%5B5%5D+%2B+a%5B6%5D+%2B+a%5B7%5D = 5,        (5)
a%5B6%5D+%2B+a%5B7%5D+%2B+a%5B8%5D = 6,        (6)
a%5B7%5D+%2B+a%5B8%5D+%2B+a%5B9%5D = 7,        (7) 
a%5B8%5D+%2B+a%5B9%5D+%2B+a%5B10%5D = 8,       (8) 
a%5B9%5D+%2B+a%5B10%5D+%2B+a%5B11%5D = 9,      (9)
a%5B10%5D+%2B+a%5B11%5D+%2B+a%5B12%5D = 10,    (10) 
a%5B11%5D+%2B+a%5B12%5D+%2B+a%5B13%5D = 11,    (11) 
a%5B12%5D+%2B+a%5B13%5D+%2B+a%5B14%5D = 12,    (12) 
a%5B13%5D+%2B+a%5B14%5D+%2B+a%5B15%5D = 13,    (13)
a%5B14%5D+%2B+a%5B15%5D+%2B+a%5B16%5D = 14,    (14)
a%5B15%5D+%2B+a%5B16%5D+%2B+a%5B17%5D = 15,    (15)
a%5B16%5D+%2B+a%5B17%5D+%2B+a%5B1%5D = 16,     (16)
a%5B17%5D+%2B+a%5B1%5D+%2B+a%5B2%5D = 17.      (17)

Add all 17 equations (1) - (17)  (both sides). You will get

 = 1 + 2 + 3 + . . . + 15 + 16 + 17 = %28%281+%2B+17%29%2F2%29%2A17 = 9*17 = 153.

Now divide both sides of the lest equation by 3, and you will get

 = 51.   (18)


Next subtract equation (1) from the equation (18). You will get

 = 51 - 1 = 50.   (19)


Next subtract equation (4) from the equation (19). You will get

 = 50 - 4 = 46.   (20)


Next subtract equation (7) from the equation (20). You will get

 = 46 - 7 = 39.   (21)


Next subtract equation (10) from the equation (21). You will get

a%5B13%5D%2Ba%5B14%5D%2Ba%5B15%5D%2Ba%5B16%5D%2Ba%5B17%5D = 39 - 10 = 29.   (22)


Next subtract equation (13) from the equation (22). You will get

a%5B16%5D%2Ba%5B17%5D = 29 - 13 = 16.   (23)


Now compare equations (23) and (16). You instantly will get 

a%5B1%5D = 16 - 16 = 0.                  (24)


Having known a%5B1%5D = 0, we can rewrite the equation (18) in the form

 = 51.   (25)

        Now we are on the finish line, finally !!!

Next subtract equation (2) from the equation (25). You will get

 = 51 - 2 = 49.   (26)


Next subtract equation (5) from the equation (25). You will get

 = 49 - 5 = 44.   (27)


Next subtract equation (8) from the equation (27). You will get

a%5B11%5D%2Ba%5B12%5D%2Ba%5B13%5D%2Ba%5B14%5D%2Ba%5B15%5D%2Ba%5B16%5D%2Ba%5B17%5D = 44 - 8 = 36.   (28)


Next subtract equation (11) from the equation (28). You will get

a%5B14%5D%2Ba%5B15%5D%2Ba%5B16%5D%2Ba%5B17%5D = 36 - 11 = 25.   (29)


As the last step, subtract equation (14) from the equation (29). You will get

a%5B17%5D = 25 - 14 = 11.   (30)


It is your answer:  a%5B17%5D = 11.

Answer.   a%5B17%5D = 11.


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