SOLUTION: What is the location of the vertex of the parabola described by this equation? x + 2 = 14(y + 2)^2

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Question 1078576: What is the location of the vertex of the parabola described by this equation?

x + 2 = 14(y + 2)^2
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x=14(y+2)^2-2
(-2, -2) from vertex form (h,k), where (y-h)+k
14y^2+56y+54=x
Can use -b/2a for y value at vertex, which is -2 here, and x=-2 as well.
y=0, x=54
y=-1 x=12
y=-2, x=-2
y-3, x=12
(-2,-2) ANSWER

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

What is the location of the vertex of the parabola described by this equation?

x + 2 = 14(y + 2)^2
This is a parabola that has a HORIZONTAL axis.

14%28y+%2B+2%29%5E2+=+x+%2B+2

%28y+%2B+2%29%5E2+=+%281%2F14%29%28x+%2B+2%29 ------- Dividing by 14

%28y+-+k%29%5E2+=+4p%28x+-+h%29 -------- Standard form of a PARABOLIC equation

Comparing the 2 equations, we see that h = - 2 and k = - 2, thereby making the coordinates of the vertex, or: