SOLUTION: Okay I have this word problem:
A collection of 40 dimes and nickels is worth $2.90. How many nickels are there?
I came up with this equation:
(d=dimes)
0.1d+0.05(40-d)=2.9
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-> SOLUTION: Okay I have this word problem:
A collection of 40 dimes and nickels is worth $2.90. How many nickels are there?
I came up with this equation:
(d=dimes)
0.1d+0.05(40-d)=2.9
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Question 107544This question is from textbook Algebra Structure and Method Book 1
: Okay I have this word problem:
A collection of 40 dimes and nickels is worth $2.90. How many nickels are there?
I came up with this equation:
(d=dimes)
0.1d+0.05(40-d)=2.9
I got an incorrect answer according to the answer in the back of the textbook, and according to the equation solver on this site, neither of the other answers were correct. Help me! This question is from textbook Algebra Structure and Method Book 1
You can put this solution on YOUR website! A collection of 40 dimes and nickels is worth $2.90. How many nickels are there?
I came up with this equation:
(d=dimes)
0.1d + 0.05(40-d)= 2.9
:
What you have should work, continuing:
.1d + 2 - .05d = 2.9; multiplied what's inside the brackets
.1d - .05d = 2.9 - 2
.05d = .9
d = .9/.05
d = 18 dimes
and
40 - 18 = 22 nickels
:
:
Check by subsitution:
.1(18) + .05(22) =
1.8 + 1.1 = 2.9
