SOLUTION: Factorise x^2p^2-8y^2p^2-4x^2q^2+32y^2q^2 Thank you so much if you choose to answer this question! The '^' symbol stands for squared.

Algebra ->  Equations -> SOLUTION: Factorise x^2p^2-8y^2p^2-4x^2q^2+32y^2q^2 Thank you so much if you choose to answer this question! The '^' symbol stands for squared.      Log On


   

Question 1070865: Factorise x^2p^2-8y^2p^2-4x^2q^2+32y^2q^2
Thank you so much if you choose to answer this question! The '^' symbol stands for squared.
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52777) About Me  (Show Source):
You can put this solution on YOUR website!
.
  x^2p^2-8y^2p^2-4x^2q^2+32y^2q^2 =   (make grouping the terms)

= %28x%5E2p%5E2-8y%5E2p%5E2%29 - %284x%5E2q%5E2-32y%5E2q%5E2%29 = 

= %28x%5E2+-+8y%5E2%29%2Ap%5E2 - 4%28x%5E2-8y%5E2%29%2Aq%5E2 = 

= %28x%5E2-8y%5E2%29%2A%28p%5E2-4q%5E2%29.

If you want/ if you need, you may continue as long as you wish / as you can.



Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

Factorise x^2p^2-8y^2p^2-4x^2q^2+32y^2q^2
Thank you so much if you choose to answer this question! The '^' symbol stands for squared.
x%5E2p%5E2+-+8y%5E2p%5E2+-+4x%5E2q%5E2+%2B+32y%5E2q%5E2

p%5E2%28x%5E2+-+8y%5E2%29+-+4q%5E2%28x%5E2+-+8y%5E2%29

%28p%5E2+-+4q%5E2%29%28x%5E2+-+8y%5E2%29

highlight_green%28%28p+-+2q%29%28p+%2B+2q%29%28x%5E2+-+8y%5E2%29%29