Question 1070336: A man and his friend are 64m apart.They will meet in 8 seconds if they walk towards each other. If they walk in same direction, the man will catch up with his friend in 32 seconds. Find the speed of the man and his friend.
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52776)   (Show Source):
You can put this solution on YOUR website! .
A man and his friend are 64m apart.They will meet in 8 seconds if they walk towards each other. If they walk in same direction,
the man will catch up with his friend in 32 seconds. Find the speed of the man and his friend.
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The speed equation when they walk towards each other is
u + v =  . (the left side and the right side represent the relative speed for this case)
The speed equation when they walk in one direction is
u - v =  . (the left side and the right side represent the relative speed for this case)
Again,
u + v = 8, (1)
u - v = 2. (2)
Add the last two equations. You will get
2u = 10, hence, u = 5.
Then from (1) v = 8 - 5 = 3.
Answer. 5 m/sec and 3 m/sec.
There is a bunch of lessons on Travel and Distance in this site.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The lessons on Travel and Distance are the part of this online textbook under the topic "Travel and distance".
Answer by josgarithmetic(39616)  (Show Source):
You can put this solution on YOUR website! their rates in meters per second are m for the MAN and f for his FRIEND.
Toward one-another, 8m+8f=64
Both in same direction, 32m-32f=64
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Better, simplify the two equations:
Now , Elimination can be used for finding both persons' rates.
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