SOLUTION: use the squeeze theorem to show: lim (x^2cos(12pi x)) = 0 x-->0

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Question 1069293: use the squeeze theorem to show:
lim (x^2cos(12pi x)) = 0
x-->0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
-1%3C=cos%2812pi%2Ax%29%3C=1
-x%5E2%3C=x%5E2cos%2812pi%2Ax%29%3C=x%5E2
So then on the left hand side,
lim%28x-%3E0%2C%28-x%5E2%29%29=0
and on the right hand side,
lim%28x-%3E0%2C%28x%5E2%29%29=0
So by the squeeze theorem,
lim%28x-%3E0%2C%28x%5E2%2Acos%2812pi%2Ax%29%29%29=0