SOLUTION: I have an assignment what's due Monday and the question says, Solve the following equation: {{{ 4^(x+1) = 16^x }}} I know you have to do something about letting them both have

Algebra ->  Equations -> SOLUTION: I have an assignment what's due Monday and the question says, Solve the following equation: {{{ 4^(x+1) = 16^x }}} I know you have to do something about letting them both have      Log On


   



Question 1069001: I have an assignment what's due Monday and the question says, Solve the following equation: ++4%5E%28x%2B1%29+=+16%5Ex++
I know you have to do something about letting them both have the same base, but I don't know what to do after that.
Please Help and Thank you!

Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Write both of them to the same base, 2 or 4, 4 is easier
4^(x+1)=(4^2)^x=4^2x
now you have the same base, so you can set the exponents equal to each other.
x+1=2x
x=1
4^2=16^1

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let us write the right side in the base 4:


16%5Ex = %284%5E2%29%5Ex = 4%5E%282x%29.


Now the equation takes the form


4%5E%28x%2B1%29 = 4%5E%282x%29.


It implies 


x + 1 = 2x  --->  x = 1.


Answer.  x = 1.


Check.  Left side is 4%5E%28x%2B1%29 = 4%5E2 = 16.

        Right side of the original equation is 16%5Ex = 16%5E1 = 16.

        Checked.

Solved.