SOLUTION: find the smallest number which is grater than 111,111,000 and divisible by 8 and 9

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Question 1066754: find the smallest number which is grater than 111,111,000 and divisible by 8 and 9
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
THE IDEA:
To be divisible by the relatively prime numbers 8 and 9 ,
a number has to be divisible by 8%2A9=72

THE HARD WAY:
Dividing %22111%2C111%2C000%22 by 72,
we get %221%2C543%2C208%22 as the quotient,
with 24 as a remainder,
so %221%2C543%2C208%22%2A72 is less than %22111%2C111%2C000%22 ,
but the next multiple of 72 is
.

EASIER:
Dividing %22111%2C111%2C000%22 by 72,
we get %221%2C543%2C208%22 as the quotient,
with 24 as a remainder,
so adding 72-24=48 to %22111%2C111%2C000%22
we get the next multiple of 72 :
%22111%2C111%2C000%22%2B48=highlight%28%22111%2C111%2C048%22%29 .

WITHOUT DIVIDING:
Like all numbers ending in %22000%22 ,
%22111%2C111%2C000%22 is divisible by 8 ,
because 1000 is divisible by 8 .
When dividing by 9 ,
the remainder can be found by adding the digits,
and repeating the digit adding with the result,
as many times as needed until you get a single digit result.
The final result is the remainder, unless it is 9 .
If the final result is 9 ,
then the number is divisible by 9 ,
and the remainder is 0 .
The sum of the digits of %22111%2C111%2C000%22 is 6 ,
so when dividing %22111%2C111%2C000%22 by 9 ,
we get a quotient N , and the remainder is 6 .
So, %22111%2C111%2C000%22=9%2AN%2B6=3%2A3%2AN%2B3%2A2=3%283n%2B2%29 is a multiple of 8 ,
and it is even a multiple of 3,
but it is not a multiple of 9 .
If I add a multiple of 8 that is also a multiple of 3 ,
such as 3%2A8=24 or 2%2A3%2A8=48 ,
the sum will also be a multiple of 8 and a multiple of 3 .
One of those sums must be a multiple of 9 too.
%22111%2C111%2C000%22%2B24=%22111%2C111%2C024%22 is not a multiple of 9 ,
because adding digits we get
%281%2B1%2B1%2B1%2B1%2B1%29%2B2%2B4=6%2B2%2B4=12 and 1%2B2=3 ,
but %22111%2C111%2C000%22%2B48=highlight%28%22111%2C111%2C048%22%29 is a multiple of 9 ,
because %281%2B1%2B1%2B1%2B1%2B1%29%2B4%2B8=6%2B4%2B8=18 and 1%2B8=9 .