SOLUTION: how do you solve function notation if h(x)=x to the second power-2x+1

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Question 1061807: how do you solve function notation if h(x)=x to the second power-2x+1
Answer by Alan3354(69443) About Me  (Show Source):
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how do you solve function notation if h(x)=x to the second power-2x+1
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If you mean find the zeroes of x^2 - 2x + 1:
x^2 - 2x + 1 = 0
(x-1)^2 = 0
x = 1 (multiplicity 2)