SOLUTION: A cyclist traveled 60 mi at a constant rate before reducing the speed by 12 mph. Another 40 mi was traveled at the reduced speed. The total time for the 100-mile trip was 8 h. Find

Algebra ->  Equations -> SOLUTION: A cyclist traveled 60 mi at a constant rate before reducing the speed by 12 mph. Another 40 mi was traveled at the reduced speed. The total time for the 100-mile trip was 8 h. Find      Log On


   



Question 1058304: A cyclist traveled 60 mi at a constant rate before reducing the speed by 12 mph. Another 40 mi was traveled at the reduced speed. The total time for the 100-mile trip was 8 h. Find the rate during the first 60 mi.
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
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A cyclist traveled 60 mi at a constant rate before reducing the speed by 12 mph. Another 40 mi was traveled at the reduced speed.
The total time for the 100-mile trip was 8 h. Find the rate during the first 60 mi.
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Setup is this equation

60%2Fx+%2B+40%2F%28x-12%29 = 8.


Here 60%2Fx is the time in hours to cover the distance of 60 km at the rate x km%2Fh.

40%2F%28x-12%29 is the time to cover 40 km at the reduced speed (x-12) km%2Fh.

Setup is done. The rest is arithmetic.

To solve equation (1), multiply both sides by x*(x-12).
Then simplify and solve the quadratic equation.

Answer. x = 20 km%2Fh.