SOLUTION: the area of the floor of a rectangular room is 60 square meters. if the perimeter of the floor is 34 meters, what are the dimensions of the floor ( solve algebraically)

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Question 1058122: the area of the floor of a rectangular room is 60 square meters. if the perimeter of the floor is 34 meters, what are the dimensions of the floor ( solve algebraically)
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
Answer by ikleyn(52778) About Me  (Show Source):
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the area of the floor of a rectangular room is 60 square meters. if the perimeter of the floor is 34 meters,
what are the dimensions of the floor ( solve algebraically)
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Let L be the length (in meters), and W be the width. Then

2L + 2W = 34,

hence

L + W = 17.

Then W = 17-L.

The area is 

A = L*W = L*(17-L) = 17L+-+L%5E2.

Thus you have an equation 

17L+-+L%5E2 = 60,   or

L%5E2+-+17L+%2B+60 = 0.

Factor the left side:

(L-5)*(L-12) = 0.

The roots are 5 and 12.

The length is 12 meters, The width is 5 meters.

Solved.

For many other examples of similar solved problems see the lesson
    - Problems on the area and the dimensions of a rectangle
in this site.