SOLUTION: the area of the floor of a rectangular room is 60 square meters. if the perimeter of the floor is 34 meters, what are the dimensions of the floor ( solve algebraically)
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Question 1058122: the area of the floor of a rectangular room is 60 square meters. if the perimeter of the floor is 34 meters, what are the dimensions of the floor ( solve algebraically) Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
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the area of the floor of a rectangular room is 60 square meters. if the perimeter of the floor is 34 meters,
what are the dimensions of the floor ( solve algebraically)
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Let L be the length (in meters), and W be the width. Then
2L + 2W = 34,
hence
L + W = 17.
Then W = 17-L.
The area is
A = L*W = L*(17-L) = .
Thus you have an equation
= 60, or
= 0.
Factor the left side:
(L-5)*(L-12) = 0.
The roots are 5 and 12.
The length is 12 meters, The width is 5 meters.