SOLUTION: What is the range of f(x)=-(x+2)^2+8 in set and interval notations

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Question 1053989: What is the range of f(x)=-(x+2)^2+8 in set and interval notations
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
What is the range of f(x)= -(x+2)^2+8 in set and interval notations
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f(x) = -(x^2 + 4x + 4) + 8
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f(x) = -x^2 -4x +4
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Vertex occurs when x = -b/(2a) = 4/(2*-1) = -2
Maximum y value = f(-2) = -(-2+2)^2+8 = 8
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Range = (-oo,8]
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Cheers,
Stan H.
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