SOLUTION: a candy store owner wants to mix jelly beans costing $4 per pound with some cherry sours costing $3.50 per pound to obtain a 10-pound mixture costing $3.85 per pound. How many poun
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Question 1053041: a candy store owner wants to mix jelly beans costing $4 per pound with some cherry sours costing $3.50 per pound to obtain a 10-pound mixture costing $3.85 per pound. How many pounds of each type on candy should be used? Answer by ikleyn(52778) (Show Source):
You can put this solution on YOUR website! .
a candy store owner wants to mix jelly beans costing $4 per pound with some cherry sours costing $3.50 per pound
to obtain a 10-pound mixture costing $3.85 per pound. How many pounds of each type on candy should be used?
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Solution 1. Two equations
Let x = the amount of the $4 jelly beans and y = the amount of the $3.50 cherry sours (in pounds) to mix.
Then you have two equations
x + y = 10,
4x + 3.50y = 3.85*10.
Simplify:
x + y = 10, (1)
4x + 3.50y = 38.5. (2)
Express x = 10-y from (1) and substitute it into (2). You will get
4(10-y) + 3.5y = 38.5.
Simplify and solve for y.
Solution 2. One equations
Let x = the amount of the $4 jelly beans (in pounds).
Then the amount of the $3.50 cherry sours (in pounds) is 10-x.
The equation is
4x + 3.50*(10-x) = 3.85*10.
Simplify and solve for x.
