SOLUTION: The perimeter of a bulletin board is 136. The length is represented as 2 more than 2 times the width. The width is represented as w. What are the dimensions of the bulletin board?

Algebra ->  Equations -> SOLUTION: The perimeter of a bulletin board is 136. The length is represented as 2 more than 2 times the width. The width is represented as w. What are the dimensions of the bulletin board?      Log On


   

Question 1052603: The perimeter of a bulletin board is 136. The length is represented as 2 more than 2 times the width. The width is represented as w. What are the dimensions of the bulletin board?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming the bulletin board is a rectangle.
P=2L%2B2W
2L%2B2W=136
L%2BW=68
and
L=2%2B2W
Substituting,
2%2B2W%2BW=68
3W=66
W=22
So then,
L%2B22=68
L=46