SOLUTION: Please help how to solve this equation. Big thanks! 3(z+2) - 4z = 2^(-(1/2)z+1) + 4

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Question 1051172: Please help how to solve this equation. Big thanks!
3(z+2) - 4z = 2^(-(1/2)z+1) + 4

Found 2 solutions by Fombitz, rothauserc:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
3%28z%2B2%29+-+4z+=+2%5E%28-%281%2F2%29z%2B1%29+%2B+4
3z%2B6-4z=2%5E%28-z%2F2%2B1%29%2B4
-z%2B6=2%5E%28-z%2F2%2B1%29%2B4
-z%2B2=2%5E%28-z%2F2%2B1%29
Graphing both sides,
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Find an intersection at z=0 and z=2.

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
3(z+2) - 4z = 2^(-(1/2)z+1) + 4
:
6 - z = 2^(1 - (z/2)) + 4
:
we have two equations
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1) 6 - z
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2) 2^(1 - (z/2)) + 4
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now graph the two equations and where they intersect/s is the solution/s for z
:
+graph%28300%2C+200%2C+-3%2C+7%2C+-1%2C+9%2C+6-x%2C+2%5E%281+-+%28x%2F2%29%29%2B4%29+
:
z is the x axis, we see there are two intersection points
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solution for z is 0 and -2
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