SOLUTION: let f(x)={{{1/(1-x)}}} write down the maclaurin series expansion of f(x)

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Question 1049862: let f(x)=1%2F%281-x%29 write down the maclaurin series expansion of f(x)
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
By the uniqueness of the Taylor (Maclaurin) expansion of a function around x = 0 within its domain of convergence,
the Maclaurin expansion of 1%2F%281-x%29 is

1+%2B+x+%2B+x%5E2+ +...+ x%5En+.....,

for -1 < x < 1.