SOLUTION: find the equation of the line containing the point p(4,5) and perpendicular to the graph of y=3/4x-3

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Question 1049563: find the equation of the line containing the point p(4,5) and perpendicular to the graph of y=3/4x-3
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Slope of any line parallel to y=(3/4)x-3 is 3%2F4.
Slope of any line perpendicular to it and in the same plane would be -4%2F3, which is the negative reciprocal.

The perpendicular line to y=(3/4)x-3, and containing (4,5), is if starting in point-slope form, y-5=-%284%2F3%29%28x-4%29. Adjust the form if you want.