SOLUTION: Hi,
Sherman is chasing his pet frog Cyrus. Sherman takes 2 steps while Cyrus makes 3 jumps, but Sherman's steps are twice as long as the frog's jumps. The frog had made 10 jumps b
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-> SOLUTION: Hi,
Sherman is chasing his pet frog Cyrus. Sherman takes 2 steps while Cyrus makes 3 jumps, but Sherman's steps are twice as long as the frog's jumps. The frog had made 10 jumps b
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Question 1049002: Hi,
Sherman is chasing his pet frog Cyrus. Sherman takes 2 steps while Cyrus makes 3 jumps, but Sherman's steps are twice as long as the frog's jumps. The frog had made 10 jumps before Sherman noticed and started chasing him. How many more jumps will Cyrus make before Sherman catches him?
I need an explanation or an illustration to explain this??Pls help Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! This is a disguised rate problem. Even though
you don't see miles/hr or km/hr, there are still
rates involved.
Put both of their rates in terms of frog jumps
Sherman's rate: frog jumps / unknown time unit
Cyrus's rate: frog jumps / unknown time unit
I could call time unit anything, so I'll just say it is 1 minute
------------------------------------------------------
Cyrus's headstart is a distance of frog jumps
Start a stopwatch when Sherman leaves
Stop the stopwatch when Sherman catches Cyrus
-------------------------------------------------
Let = distance in frog jumps
Let = time in minutes
Sherman's equation:
(1)
Cyrus's equation:
(2)
------------------------
(1)
Substitute this into (2)
(2)
(2)
(2)
-------------------
This tells me that Sherman makes frog jumps
from start to stop of stopwatch.
In that time, Cyrus has made: frog jumps which is the answer
----------------------------
check the answer:
(1)
(1)
(1) min
and
(2)
(2)
(2)
(2) min
So, 10 min shows on the stopwatch- not the best
time unit to choose, but you can pick any.
OK
