SOLUTION: x^2 + ix + 2 = 0 I'm supposed to be finding the roots of the equation "i" is a complex number My answer was x= (-i+/-3)/2 The correct answer was -2i,i Where did I go wrong

Algebra ->  Equations -> SOLUTION: x^2 + ix + 2 = 0 I'm supposed to be finding the roots of the equation "i" is a complex number My answer was x= (-i+/-3)/2 The correct answer was -2i,i Where did I go wrong      Log On


   



Question 1048912: x^2 + ix + 2 = 0
I'm supposed to be finding the roots of the equation
"i" is a complex number
My answer was x= (-i+/-3)/2
The correct answer was -2i,i
Where did I go wrong

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+%2B+ix+%2B+2+=+0
use quadratic formula:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-i+%2B-+sqrt%28+i%5E2-4%2A1%2A2+%29%29%2F%282%2A1%29+
x+=+%28-i+%2B-+sqrt%28+-1-8+%29%29%2F2+
x+=+%28-i+%2B-+sqrt%28+-9+%29%29%2F2+
x+=+%28-i+%2B-+3i%29%2F2+
solutions:
x+=+%28-i+%2B+3i%29%2F2+
x+=+2i%2F2+
highlight%28x+=+i%29
x+=+%28-i+-+3i%29%2F2+
x+=+%28-4i%29%2F2+
highlight%28x+=+-2i%29+