SOLUTION: A person has quarters and dimes that total $2.80. The number of dimes is 7 more than the number of quarters. How many of each coin does the person have?

Algebra ->  Equations -> SOLUTION: A person has quarters and dimes that total $2.80. The number of dimes is 7 more than the number of quarters. How many of each coin does the person have?      Log On


   

Question 1048612: A person has quarters and dimes that total $2.80. The number of dimes is 7 more than the number of quarters. How many of each coin does the person have?
Answer by solver91311(24713) About Me  (Show Source):
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Let represent the number of quarters. Then must be the number of dimes. There are cents in quarters. There are cents in dimes. $2.80 is 280 cents.



Solve for then calculate

John

My calculator said it, I believe it, that settles it