Question 1047635: Solve.
8x-3<8(x+2)
can you please show steps to the solution
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! 8x-3<8(x+2)
8x-3<8x+16
subtract 8x from both sides
-3<16. This is true. Therefore, every x works and there are infinite solutions.
Try 0
-3<16 yes
Try 10
77<8(12) yes
Try -10
-83<8(-8) yes
For an equality, -3=16 means no solutions.
For an inequality, -3>16 means no solutions, but -3<16 means infinite number of solutions.
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