SOLUTION: What is the equation of a line with a slope of -5/7 that crosses the y-axis at -1?

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Question 1046820: What is the equation of a line with a slope of -5/7 that crosses the y-axis at -1?
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Using the point slope form,
y-y%5B1%5D=-%285%2F7%29%28x-x%5B1%5D%29
with the point (0,-1),
y-%28-1%29=-%285%2F7%29%28x-0%29
y%2B1=-%285%2F7%29x
y=-%285%2F7%29x-1

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
***Using point-slope form, y+-+y%5B1%5D+=+highlight_green%28m%29%28x+-+x%5B1%5D%29
line with a slope of -5/7 that crosses the y-axis at -1 ... P(0,-1)
y + 1 = (-5/7)(x-0)
y = (-5/7)x - 1
0r
5x + 7y = -7