SOLUTION: a school has fewer than 200 pupils When they line up on rows of 4 there is 1 extra pupils When they line up on rows of 5 there is 2 extra pupils When they line up on rows of

Algebra ->  Equations -> SOLUTION: a school has fewer than 200 pupils When they line up on rows of 4 there is 1 extra pupils When they line up on rows of 5 there is 2 extra pupils When they line up on rows of      Log On


   



Question 1045308: a school has fewer than 200 pupils
When they line up on rows of 4 there is 1 extra pupils
When they line up on rows of 5 there is 2 extra pupils
When they line up on rows of 6 there is 3 extra pupils
how many pupils could here be in the school?

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
N = number of pupils in the school.
When they line up on rows of 4 there is 1 extra pupil left over.
If 3 more pupils were enrolled, there would be N%2B3 pupils,
and they could line up in rows of 4 without any extra pupil left over, because the 3 new pupils plus the 1 pupil previously left over
would form another row of 3%2B1=4 pupils.
So, let's enroll 3 more pupils, because N%2B3 is a multiple of 4 ,
and then we can line them all in rows of 4 without leaving any extra pupils.
But what if we want to line them in rows of 5 ?
Well, that works too. We can group the 3 newly enrolled pupils with the 2 extra pupils that were left over when we only had N pupils,
and they could form a new row of 3%2B2=5 pupils.
It turns out that N%2B3 is a multiple of 5 too.
All right, so N%2B3 is a good number of pupils if we want to line them up in rows of 4 or 5 ,
but what if we want to line them up in rows of 6 ?
It did not work with N pupils, because we had 3 extra pupils left over.
With those 3 pupils, and the 3 newly enrolled pupils, we can make a new row with 3%2B3=6 pupils.
Wow! It turns out that N%2B3 is a multiple of 6 too.
So, N%2B3 is the right number of pupils for a school that likes to line them up in even rows.
That N%2B3 must be a magical number. It is a multiple of
4 , 5 and 6 .
The least common multiple of 4 , 5 and 6 is
60=6%2A10 ,
the smaller multiple of 6 that is also a multiple of 4 , 5 :
60=4%2A15 and 60=5%2A12 .
So, it could be that
N%2B3=60 --> N=60-3 ---> highlight%28N=57%29 ,
or it could be that
N%2B3=60%2A2=120 --> N=120-3 ---> highlight%28N=117%29 ,
or it could be that
N%2B3=60%2A3=180 --> N=180-3 ---> highlight%28N=177%29 .
The next multiple of 60 , 4%2A60=240 , does not work,
because N%2B3=240 <---> N=240-3=237 makes the number of pupils greater than 200 .
So the school could have highlight%2857%29 pupils, or highlight%28117%29 pupils, or highlight%28177%29 pupils.