SOLUTION: A farmer had 15 animals in its farmyard. Some were chickens and some were cows. There were 52 legs in all. How many cows were in the farmyard?
Algebra ->
Equations
-> SOLUTION: A farmer had 15 animals in its farmyard. Some were chickens and some were cows. There were 52 legs in all. How many cows were in the farmyard?
Log On
Question 1045157: A farmer had 15 animals in its farmyard. Some were chickens and some were cows. There were 52 legs in all. How many cows were in the farmyard? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! x=chickens
y=cows
x+y=15
2x+4y=52
-2x-2y=-30, multiplying the first equation by -2. Now add them.
2y=22
y=11 cows and 44 lege
x=4 chickens and 8 legs