SOLUTION: Find an equation of the tanget line to the following graph at the given point In(x+1)+e^(x+y^2)=1 ,p(0,0)

Algebra ->  Equations -> SOLUTION: Find an equation of the tanget line to the following graph at the given point In(x+1)+e^(x+y^2)=1 ,p(0,0)      Log On


   



Question 1044352: Find an equation of the tanget line to the following graph at the given point
In(x+1)+e^(x+y^2)=1 ,p(0,0)

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The tangent line at the point (0,0) will NOT exist, as the derivative at (0,0) doesn't exist there.
Although the point (0,0) is a point on the curve, the relation is not differentiable at that point.
Using implicit differentiation,
1%2F%28x%2B1%29+%2B+e%5E%28x%2By%5E2%29%2A%281%2B2y%2A%28dy%2Fdx%29%29+=+0.
Substituting the coordinates of (0,0) into this differential equation would give
.