SOLUTION: What is the equation of the midline for this function? y = 3sec (Θ - 2) + 3 A.) y = 2 B.) y = -2 C.) y = 3 D.) y = -3

Algebra ->  Equations -> SOLUTION: What is the equation of the midline for this function? y = 3sec (Θ - 2) + 3 A.) y = 2 B.) y = -2 C.) y = 3 D.) y = -3      Log On


   

Question 1040767: What is the equation of the midline for this function?
y = 3sec (Θ - 2) + 3
A.) y = 2
B.) y = -2
C.) y = 3
D.) y = -3
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.
The term "midline for the function" is not defined in math and is never used in math.

You are the first person in the world who uses it.


Comment from student: Wtf? I asked "What is the equation of the midline for this function? Of course "midline for the function" is not a term.
I was asking what the midline for the specific function I listed was.
"The equation of the midline of periodic function is the average of the maximum and minimum values of the function."
(http://www.icoachmath.com/math_dictionary/midline.html)


My responce: Thank you for your comment.
It means that you are not the first . . . (I was wrong in that sense).
Then the answer is "In this case midline is y = 3".

See the plot below.



Figure. Plot y = 3sec (Θ - 2) + 3

Let me continue.
The next phrase in that page you refer to, is

      "More About Midline
      The equation of the midline of periodic function is the average of the maximum and minimum values of the function"

Thus the value y = 3 is exactly in half way between -infinity and infinity that are the minimum and the maximum in your case.

In my view, the entire page and all their definitions are nonsence.

Excuse me for these explanations.
And have a nice afternoon.