SOLUTION: How do you divide an algebraic fraction when one of the terms in the denominator is bigger than the one on top (with also the same term) but the other terms on the denominator divi

Algebra ->  Equations -> SOLUTION: How do you divide an algebraic fraction when one of the terms in the denominator is bigger than the one on top (with also the same term) but the other terms on the denominator divi      Log On


   

Question 1037536: How do you divide an algebraic fraction when one of the terms in the denominator is bigger than the one on top (with also the same term) but the other terms on the denominator divides perfectly by the ones on top... EG (x^2+14x-18/2x^2+x-6)=1
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Unclear description.

(x^2+14x-18/2x^2+x-6)=1
Also not fully clear.


Put in the missing grouping symbols.
(x^2+14x-18)/(2x^2+x-6)=1
%28x%5E2%2B14x-18%29%2F%282x%5E2%2Bx-6%29=1

That numerator seems to be not factorable. Maybe you could still try to solve the equation for the variable. Your question was about dividing one expression by another. Try POLYNOMIAL LONG DIVISION.

... Why do you have your rational expression set equal to 1?
x%5E2%2B14x-18=2x%5E2%2Bx-6 would be an equivalent equation although potentially without the same restriction.
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2x%5E2-x%5E2%2Bx-14x-6%2B18=0
x%5E2-13x%2B12=0
%28x-1%29%28x-12%29=0
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SOLUTION, system%28x=1%2C+or%2C+x=12%29


Do either of these fail in the original equation? Look at the denominator.
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2x%5E2%2Bx-6
2%281%29%5E2%2B1-6
2%2B1-6
-3
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2%2A12%5E2%2B12-6
288%2B6
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Neither of those are 0, so both solutions will work.