Question 1035767: a/(a-1)=1-(1/a)
how do i solve this equation and check for extraneous solutions? Found 2 solutions by Alan3354, Boreal:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! a/(a-1)=1-(1/a)
how do i solve this equation and check for extraneous solutions?
------------
a/(a-1)=1-(1/a)
a/(a-1)=(a-1)/a
a^2 = a^2 - 2a + 1
2a = 1
a = 1/2
-------
You can put this solution on YOUR website! a/(a-1)=1-(1/a)
rewrite
a/(a-1)= (a-1)/a; the second part is (a/a)-(1/a) or 1- (1/a)
multiply both sides by the common denominator a(a-1)
a^2=(a-1)^2
don't take the square root
a^2=a^2-2a+1
2a=1
a=(1/2) ANSWER
(1/2)/(-1/2)=1-(1/(1/2)), the second part is 1-2=-1
-1=1-2=-1
