Question 1034486: Three people are to share an amount of money in the following parts: 1/2, 1/3, and 1/6. Each person takes some money from this amount of money until there is nothing left. The first person then returns 1/2 of what he took. The second person then returns 1/3 of what he took, and the third person returns 1/6 of what he took. When the total of what was returned is divided equally among the three, each has his correct share, namely, 1/2, 1/3, and 1/6. How much money was in the original amount and how much did each person get from the original amount of money?
Answer by robertb(5830)   (Show Source):
You can put this solution on YOUR website! Let guy A get 1/2 of the original amount, guy B get 1/3, and guy C get 1/6.
ANSWER: The original amount would be 47 times of whatever guy C took initially.
Guy B took 13 times as much as what guy C took initially, and guy A took 33 times as much as what guy C took initially.
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